If (x1, y1) and (x2, y2) are two points or coordinates in XP plane, then we can find the distance between them by following mathematical distance formula:

This formula was made from Pythagoras triangle theorem.

Now let’s see how to find distance between two points in Java:

If (x1, y1) and (x2, y2) are two points or coordinates in XP plane, then following java console program shows the distance between them.

**Java Program for Finding Distance between Two Points**

```
import java.io.*;
class distance
{
int x1,y1,x2,y2,difx,dify;
double d;
void get() throws IOException
{
BufferedReader Br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("\n Enter the X part of first point : ");
x1=Integer.parseInt(Br.readLine());
System.out.print(" Enter the Y part of first point : ");
y1=Integer.parseInt(Br.readLine());
System.out.print("\n Enter the X part of second point : ");
x2=Integer.parseInt(Br.readLine());
System.out.print(" Enter the Y part of second point : ");
y2=Integer.parseInt(Br.readLine());
}
void display()
{
difx = (x2 - x1) * (x2 - x1);
dify = (y2 - y1) * (y2 - y1);
d = Math.sqrt(difx + dify);
System.out.println("\n Distance between (" + x1 + "," + y1 + ") and (" + x2 + "," + y2 + ") is : " + d + " unit(s) " );
}
public static void main(String p[]) throws IOException
{
distance dis = new distance();
dis.get();
dis.display();
}
}
```

__Sample Output:__

Enter the X part of first point : 1

Enter the Y part of first point : 4

Enter the X part of second point : 4

Enter the Y part of second point : 0

Distance between (1, 4) and (4, 0) is : 5.0 unit(s).

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