This is a common question in C++ practical examinations. Here the program accept an integer number and calculate the individual digits and display the sum on the screen.

For example if you give the number *12345*, then sum of individual digits is 15 (1 + 2 + 3 + 4 + 5 = 15).

__Program:__

__Program:__

```
#include <iostream>
using namespace std;
int main()
{
int num,lastDigit,sum=0,balNum;
cout <<"Enter a number : ";
cin>>num;
balNum = num;
while(balNum>0)
{
lastDigit = balNum % 10;
balNum = balNum /10;
sum = sum + lastDigit;
}
cout<<"Sum of individual digits of "<<num<<" is = "<<sum;
return 0;
}
```

__Code Explanation:__

__Code Explanation:__

Variable ‘num’ accepts an input number of integer datatype.

**balNum = num;**

Here our original number ‘num’ is copied into variable ‘balNum’, because at last of program, we need our original number.

**lastDigit = balNum % 10;**

Here last digit of the number is assigned into the variable *lastDigit* using modulus operator (%).

For example: If the number is 12345, then 12345 % 10 is the remainder of the division operation 12345 / 10, that is 5. At *while loop* we repeat this process to get each individual digits.

*balNum = balNum /10;*

If we got the last digit, then we don’t need the last number. So we can avoid this number by division operation. That is 12345 / 10 is 1234 (Integer datatype does not support exponential part).

*sum = sum + lastDigit;*

The variable ‘*sum*‘ is added into same variable after adding last digit of the number.

‘w*hile loop*‘ continues these steps until the value of the balNum is 0.

__Sample Output:__

__Sample Output:__

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